t^2-5t+15=0

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Solution for t^2-5t+15=0 equation: 



t^2-5t+15=0

a = 1; b = -5; c = +15;
Δ = b2-4ac
Δ = -52-4·1·15
Δ = -35
Delta is less than zero, so there is no solution for the equation

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